This issue has been automatically converted from the original issue lists and some formatting may not have been preserved.
Authors: WG14, Clive Pygott
Date: 2014-03-11
Reference document: N1801
Submitted against: C Secure Coding Rules TS 17961:2013
Status: Fixed
Fixed in: C Secure Coding Rules TS 17961:2013 TC1
Converted from: n2150.htm
The (cut-down) requirement for rule 5.21 is:
A call to a standard memory allocation function is presumed to be intended for type T * when it appears in any of the following contexts
A call to a standard memory allocation function taking a size integer argument n and presumed to be intended for type T * shall be diagnosed when n < sizeof(T).
{malloc is identified as a standard memory allocation function}
The example for 5.21 is:
wchar_t *f1(void) {
const wchar_t *p = L"Hello, World!";
const size_t n = sizeof(p) * (wcslen(p) + 1);
wchar_t *q = (wchar_t *)malloc(n); // diagnostic required
/* ... */
return q;
}
Why is a diagnostic required on the malloc statement? On my machine
56 is not less than 2, so no diagnostic is required.
Indeed, the only values of n that would require a diagnostic are 0 and 1.
I think the original intent was to make q smaller than 28 (the space required for 14 wide characters), then copy p to q (buffer overrun), but this rule doesn’t actually address that and the copy isn’t included in the example. That is, I think the original example was to be of the form:
wchar_t *f2(void) {
const wchar_t *p = L"Hello, World!";
const size_t n = /*sizeof(p) * */ (wcslen(p) + 1); /* NB n == 14 */
wchar_t *q = (wchar_t *)malloc(n);
wcscpy(q, p);
return q;
}
This does have an issue - buffer overrun, but still doesn’t violate 5.21 as currently stated (14 is still >= 2). I think the reason 5.21 got changed was either:
Either 5.21 needs a different example, such as :
struct S1 { int x, y, z;}; /* sizeof(S1) is 12 */
struct S1 *copyS1(const struct S1 s) {
struct S1 *q = (struct S1 *)malloc(8); /* Diagnostic required */
*q = s;
return q;
}
or the rule needs to be changed to reflect that the allocated memory is in effect an array of size n/sizeof(T), and that it shouldn’t be indexed beyond that size (including by copy functions such as wcscpy etc. - this caveat may also need to be added to 5.22)
I'd favour changing the example
Comment from WG14 on 2016-10-21:
Apr 2014 meeting
The words in 5.21 were revised but the example wasn't. A revised example was approved as a Proposed Technical Corregendum. A new paper was solicited to capture the issue raised by the changed example.
Oct 1014 meeting
A new paper N1860 proposing a new rule was submitted and discussed, and it was determined that since the original example illustrated an issue, that we could consider this a defect after all.
The following Proposed Technical Corrigendum corrects the existing example to match the 5.21 rule, and adds a new clause and example to capture the intent of the original 5.21 example.
The existing example has an explanation, and the words approved do not, and the following have been suggested.
EXAMPLE 1 In this noncompliant example, a diagnostic is required because
n
issizeof(p)
, which is smaller thansizeof(struct S1)
, so N is 0EXAMPLE 2 In this noncompliant example, a diagnostic is required because
n
is 14 andsizeof(wchar_t)
is 2, making N equal 7.q
is therefore treated as an array of 7 elements, butwcscpy
attempts to copyp
, an array with 14 elements, into it.
In rule 5.21, Rule section, replace
A call to a standard memory allocation function taking a size integer argument
n
and presumed to be intended for typeT *
shall be diagnosed whenn < sizeof(T)
.
with
A call to a standard memory allocation function taking a size integer argument
n
and presumed to be intended for typeT *
shall be regarded as an array ofN
elements, whereN = n / sizeof(T)
.Any allocation where
N == 0
shall be diagnosed (i.e. wheren < sizeof(T)
). Also, any attempt to use this array in a manner that causes its array bound to be violated shall be diagnosed.
In rule 5.21, replace
EXAMPLE In this noncompliant example, a diagnostic is required because the value of
n
that is used in themalloc()
call has been possibly miscalculated.wchar_t *f1(void) { const wchar_t *p = L"Hello, World!"; const size_t n = sizeof(p) * (wcslen(p) + 1); wchar_t *q = (wchar_t *)malloc(n); // diagnostic required /* ... */ return q; }
with
EXAMPLE 1 struct S1 { unsigned int x; float y; struct S1 *z; }; struct S1 *f1(void) { struct S1 *p = (struct S1*)malloc(sizeof(p)); // diagnostic required return p; } EXAMPLE 2 wchar_t *f2(void) { const wchar_t *p = L"Hello, World!"; const size_t n = (wcslen(p) + 1); wchar_t *q = (wchar_t *)malloc(n); wcscpy(q, p); // diagnostic required return q; }