Issue 0017.09: What is the type of an assignment expression?

This issue has been automatically converted from the original issue lists and some formatting may not have been preserved.

Authors: Derek M. Jones, WG14
Date: 1992-12-10
Reference document: X3J11/90-056
Submitted against: C90
Status: Fixed
Fixed in: C90 TC1
Converted from: dr.htm, dr_017.html

Syntax of assignment expression

In subclause 6.3.16.1 on page 53, lines 31-32 there is a typo: “... of the assignment expression ...” should be “... of the unary expression ...”

In subclause 6.3.16 on page 53, lines 3-5 we have

assignment-expression:
    ...
         unary-expression  assignment-operator  assignment-expression

Now the string “assignment-expression” occurs twice.

The use of “assignment expression” in subclause 6.3.16 on page 53, line 12 refers to the first occurrence (the one to the left of the colon).

We suggest changing the use of “assignment expression” in subclause 6.3.16.1 on page 53, line 32 in order to prevent confusion. The fact that any qualifier is kept actually makes more sense, since this qualifier has to take part in any constraint checking.

Comment from WG14 on 1997-09-23:

Correction

Add to subclause 6.3.16.1, page 54, another Example:

In the fragment:

   char c;
    int i;
    long l;

    l = ( c = i );

the value of i is converted to the type of the assignment-expression c = i, that is, char type. The value of the expression enclosed in parenthesis is then converted to the type of the outer assignment-expression, that is, long type.